Chemical Bonding: The Valence Bond Approach
(outline, part 3)
Valence Shell Electron Pair Repulsion Theory (VSEPR Theory)
Assumption:
VSEPR Rules
1. Electron pairs tend to _____________ repulsions. For a given no. of electron pairs around the central atom (the occupancy) certain geometries will minimize electron pair repulsions.
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Ideal Geometry of e- prs. |
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BF3 (CN = 3, trig. planar) SO2 (CN = 2, bent) |
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CH4 (CN = 4, tetrahed.) NH3 (CN = 3, trig. pyr.) H2O (CN = 2, bent) |
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trans. metal cmplxs, d8 PtCl42- |
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PF5 |
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SF6 |
Note that when the occupancy (the total no. of electron pairs around the central atom) equals the coordination number (CN), then the name for the geometry of the electron pairs will be the same as the name of the geometry of the molecule. When CN is less than the occupancy, then the name of the geometry will be different. For example, water, H2O, has an approximately tetrahedral arrangement of electrons around the oxygen (occupancy = 4). However, the geometry is bent, not tetrahedral since only two atoms are bonded to oxygen (so CN = 2).
2. Repulsions increase in the order BP-BP BP-LP LP-LP.
a. When lone pairs are present, the bond angles are ___________ than predicted by rule 1.
CH4 vs NH3
A closer look at lone pairs:

Stick and ball model of ammonia.

Electrostatic potential isosurface for NH3. This shows where a proton would protonate NH3.
To a first approximation we can think of the NH3 HOMO as being equivalent to a lone pair on nitrogen:

NH3 HOMO. (Highest occupied molecular orbital)
Another view:

Stick and ball model of NH3.

Electrostatic potential contour plot for NH3. Magenta means negative potential energy. Again this shows where the proton would want to go and hence, where the lone pair is.
b. Lone pairs chose the ___________ site, e.g._____________________________
BrF3
c. If all sites are equal, lone pairs will be ___________________
XeF4
3. Double bonds ____________________________________
SOF4

Stick and ball model of SOF4.

Bonding electron density isosurface.
Which bond is "thicker"?

Electron density contour plot.
S=O bond is __________ than S-F bonds therefore F-S-F angle (equatorial) is < 120o
4. Bonding pairs to electronegative substituents occupy __________ space than those to more electropositive substituents.
X-P-X bond angles:
PF3 = 97.8o < PCl3 = 100.3o < PBr3 = 101.5o < PI3 = 102o
Why?
Y-N-Y bond angles in NY3 :
NF3 = ____ NH3 = ____
Why?
Examples:
SO3
SO32-
SO2
SF4

Electron density contour plot of SF4.

Stick & ball model of SF4.

Electrostatic potential map for SF4.
Note the axial F atoms are more electron rich than the equatorial ones.